题目如下：

Given two sequences pushed and popped with distinct values, return true if and only if this could have been the result of a sequence of push and pop operations on an initially empty stack.

 

Example 1:

Input: pushed = [1,2,3,4,5], popped = [4,5,3,2,1]Output: trueExplanation: We might do the following sequence:push(1), push(2), push(3), push(4), pop() -> 4,push(5), pop() -> 5, pop() -> 3, pop() -> 2, pop() -> 1

Example 2:

Input: pushed = [1,2,3,4,5], popped = [4,3,5,1,2]Output: falseExplanation: 1 cannot be popped before 2.

 

Note:

1. 0 <= pushed.length == popped.length <= 1000
2. 0 <= pushed[i], popped[i] < 1000
3. pushed is a permutation of popped.
4. pushed and popped have distinct values.

解题思路：栈具有后进先出的特性，从这个特性中可以得出这么一个规律：对于出栈序列中的任意一个元素来说，在这个元素之前入栈的其他元素并且在这个元素之后出栈的这些元素必定满足后进先出。以 pushed = [8,2,1,4,7,9,0,3,5,6]，popped = [1,2,7,3,6,4,0,9,5,8] 为例，对于元素3来说，在其之前入栈的元素为[8,2,1,4,7,9,0]，在其后出栈的元素为[6,4,0,9,5,8] ,同时满足先于3入栈后于3出栈的元素为[8,4,9,0]，这些元素出栈的顺序必定要满足[0,9,4,8]的顺序。所以只要遍历[8,4,9,0]序列，判断这些元素的在popped数组中的索引是否是递减即可。

代码如下：

class Solution(object):    def validateStackSequences(self, pushed, popped):        """        :type pushed: List[int]        :type popped: List[int]        :rtype: bool        """        dic_push = {}        dic_pop = {}        for i,v in enumerate(pushed):            dic_push[v] = i        for i, v in enumerate(popped):            dic_pop[v] = i        for i,v in enumerate(popped):            push_inx = dic_push[v]            lastInx = len(popped)            for j in range(push_inx):                if dic_pop[pushed[j]] < i:                    continue                elif dic_pop[pushed[j]] > lastInx :                    return False                lastInx = dic_pop[pushed[j]]        return True